Base | Representation |
---|---|
bin | 110001011101000001… |
… | …101110110010001011 |
3 | 12002001122122212212120 |
4 | 301131001232302023 |
5 | 1332222141424121 |
6 | 40221032342323 |
7 | 3556606314624 |
oct | 613501566213 |
9 | 162048585776 |
10 | 53100342411 |
11 | 20579839206 |
12 | a35b2449a3 |
13 | 501318786c |
14 | 27da3b6a4b |
15 | 15abb59bc6 |
hex | c5d06ec8b |
53100342411 has 8 divisors (see below), whose sum is σ = 71094235344. Its totient is φ = 35253338880.
The previous prime is 53100342391. The next prime is 53100342431. The reversal of 53100342411 is 11424300135.
It is a happy number.
53100342411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (53100342391) and next prime (53100342431).
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 53100342411 - 213 = 53100334219 is a prime.
It is not an unprimeable number, because it can be changed into a prime (53100342431) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 36721506 + ... + 36722951.
It is an arithmetic number, because the mean of its divisors is an integer number (8886779418).
Almost surely, 253100342411 is an apocalyptic number.
53100342411 is a deficient number, since it is larger than the sum of its proper divisors (17993892933).
53100342411 is a wasteful number, since it uses less digits than its factorization.
53100342411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 73444701.
The product of its (nonzero) digits is 1440, while the sum is 24.
Adding to 53100342411 its reverse (11424300135), we get a palindrome (64524642546).
The spelling of 53100342411 in words is "fifty-three billion, one hundred million, three hundred forty-two thousand, four hundred eleven".
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