Base | Representation |
---|---|
bin | 100110101000101011111… |
… | …0100101101111001010101 |
3 | 200210122011201120020100211 |
4 | 1031101113310231321111 |
5 | 1143444442032441000 |
6 | 15143223224405421 |
7 | 1055432030622505 |
oct | 115212764557125 |
9 | 20718151506324 |
10 | 5310053015125 |
11 | 1767a87548921 |
12 | 71915a016871 |
13 | 2c6974882c21 |
14 | 145017acba05 |
15 | 931d77617ba |
hex | 4d457d2de55 |
5310053015125 has 16 divisors (see below), whose sum is σ = 6627114104832. Its totient is φ = 4247934757200.
The previous prime is 5310053015123. The next prime is 5310053015147. The reversal of 5310053015125 is 5215103500135.
It is not a de Polignac number, because 5310053015125 - 21 = 5310053015123 is a prime.
It is a super-3 number, since 3×53100530151253 (a number of 39 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5310053015123) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4610112 + ... + 5645638.
It is an arithmetic number, because the mean of its divisors is an integer number (414194631552).
Almost surely, 25310053015125 is an apocalyptic number.
It is an amenable number.
5310053015125 is a deficient number, since it is larger than the sum of its proper divisors (1317061089707).
5310053015125 is a wasteful number, since it uses less digits than its factorization.
5310053015125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1076565 (or 1076555 counting only the distinct ones).
The product of its (nonzero) digits is 11250, while the sum is 31.
The spelling of 5310053015125 in words is "five trillion, three hundred ten billion, fifty-three million, fifteen thousand, one hundred twenty-five".
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