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5310053015125 = 53410231035527
BaseRepresentation
bin100110101000101011111…
…0100101101111001010101
3200210122011201120020100211
41031101113310231321111
51143444442032441000
615143223224405421
71055432030622505
oct115212764557125
920718151506324
105310053015125
111767a87548921
1271915a016871
132c6974882c21
14145017acba05
15931d77617ba
hex4d457d2de55

5310053015125 has 16 divisors (see below), whose sum is σ = 6627114104832. Its totient is φ = 4247934757200.

The previous prime is 5310053015123. The next prime is 5310053015147. The reversal of 5310053015125 is 5215103500135.

It is not a de Polignac number, because 5310053015125 - 21 = 5310053015123 is a prime.

It is a super-3 number, since 3×53100530151253 (a number of 39 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5310053015123) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4610112 + ... + 5645638.

It is an arithmetic number, because the mean of its divisors is an integer number (414194631552).

Almost surely, 25310053015125 is an apocalyptic number.

It is an amenable number.

5310053015125 is a deficient number, since it is larger than the sum of its proper divisors (1317061089707).

5310053015125 is a wasteful number, since it uses less digits than its factorization.

5310053015125 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1076565 (or 1076555 counting only the distinct ones).

The product of its (nonzero) digits is 11250, while the sum is 31.

The spelling of 5310053015125 in words is "five trillion, three hundred ten billion, fifty-three million, fifteen thousand, one hundred twenty-five".

Divisors: 1 5 25 125 41023 205115 1025575 1035527 5127875 5177635 25888175 129440875 42480424121 212402120605 1062010603025 5310053015125