Base | Representation |
---|---|
bin | 1111011101000101101… |
… | …11111000011110011001 |
3 | 1212202122020122120010201 |
4 | 13232202313320132121 |
5 | 32200003431120031 |
6 | 1043535542542201 |
7 | 53236003402531 |
oct | 7564267703631 |
9 | 1782566576121 |
10 | 531013535641 |
11 | 19522432a896 |
12 | 86ab7437961 |
13 | 3b0c74abcb4 |
14 | 1b9b61004c1 |
15 | dc2d713d61 |
hex | 7ba2df8799 |
531013535641 has 2 divisors, whose sum is σ = 531013535642. Its totient is φ = 531013535640.
The previous prime is 531013535597. The next prime is 531013535687. The reversal of 531013535641 is 146535310135.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 379462160025 + 151551375616 = 616005^2 + 389296^2 .
It is a cyclic number.
It is not a de Polignac number, because 531013535641 - 211 = 531013533593 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 531013535641.
It is not a weakly prime, because it can be changed into another prime (531013635641) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265506767820 + 265506767821.
It is an arithmetic number, because the mean of its divisors is an integer number (265506767821).
Almost surely, 2531013535641 is an apocalyptic number.
It is an amenable number.
531013535641 is a deficient number, since it is larger than the sum of its proper divisors (1).
531013535641 is an equidigital number, since it uses as much as digits as its factorization.
531013535641 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81000, while the sum is 37.
Adding to 531013535641 its reverse (146535310135), we get a palindrome (677548845776).
The spelling of 531013535641 in words is "five hundred thirty-one billion, thirteen million, five hundred thirty-five thousand, six hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •