Base | Representation |
---|---|
bin | 110001011101000101… |
… | …110000111111101001 |
3 | 12002001201122121200001 |
4 | 301131011300333221 |
5 | 1332222424300131 |
6 | 40221111143001 |
7 | 3556621311244 |
oct | 613505607751 |
9 | 162051577601 |
10 | 53101400041 |
11 | 2057a3a0888 |
12 | a35b674a61 |
13 | 5013468091 |
14 | 27da5b025b |
15 | 15abcb8261 |
hex | c5d170fe9 |
53101400041 has 2 divisors, whose sum is σ = 53101400042. Its totient is φ = 53101400040.
The previous prime is 53101400021. The next prime is 53101400161. The reversal of 53101400041 is 14000410135.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 46733360041 + 6368040000 = 216179^2 + 79800^2 .
It is a cyclic number.
It is not a de Polignac number, because 53101400041 - 219 = 53100875753 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 53101399991 and 53101400018.
It is not a weakly prime, because it can be changed into another prime (53101400021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26550700020 + 26550700021.
It is an arithmetic number, because the mean of its divisors is an integer number (26550700021).
Almost surely, 253101400041 is an apocalyptic number.
It is an amenable number.
53101400041 is a deficient number, since it is larger than the sum of its proper divisors (1).
53101400041 is an equidigital number, since it uses as much as digits as its factorization.
53101400041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 240, while the sum is 19.
Adding to 53101400041 its reverse (14000410135), we get a palindrome (67101810176).
The spelling of 53101400041 in words is "fifty-three billion, one hundred one million, four hundred thousand, forty-one".
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