Base | Representation |
---|---|
bin | 111100010111101100110111… |
… | …0000000010000011101001110 |
3 | 2120122012022012202000211120100 |
4 | 1320233121232000100131032 |
5 | 1024100240112044312024 |
6 | 5121220334244431530 |
7 | 216565101162064323 |
oct | 17057315600203516 |
9 | 2518168182024510 |
10 | 531023012104014 |
11 | 14422265a6560a1 |
12 | 4b6839983a85a6 |
13 | 19a3c341808061 |
14 | 951b9181acb4a |
15 | 415d1d933e7c9 |
hex | 1e2f66e01074e |
531023012104014 has 48 divisors (see below), whose sum is σ = 1152514614625920. Its totient is φ = 176705435761920.
The previous prime is 531023012104007. The next prime is 531023012104021. The reversal of 531023012104014 is 410401210320135.
531023012104014 is a `hidden beast` number, since 5 + 3 + 1 + 0 + 230 + 1 + 21 + 0 + 401 + 4 = 666.
It is an interprime number because it is at equal distance from previous prime (531023012104007) and next prime (531023012104021).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 181328434 + ... + 184233674.
It is an arithmetic number, because the mean of its divisors is an integer number (24010721138040).
Almost surely, 2531023012104014 is an apocalyptic number.
531023012104014 is an abundant number, since it is smaller than the sum of its proper divisors (621491602521906).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
531023012104014 is a wasteful number, since it uses less digits than its factorization.
531023012104014 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2922585 (or 2922582 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 27.
Adding to 531023012104014 its reverse (410401210320135), we get a palindrome (941424222424149).
The spelling of 531023012104014 in words is "five hundred thirty-one trillion, twenty-three billion, twelve million, one hundred four thousand, fourteen".
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