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531023042451113 is a prime number
BaseRepresentation
bin111100010111101100110111…
…1110100000001011010101001
32120122012022021212010121221222
41320233121233310001122221
51024100240142331413423
65121220341251111425
7216565102011036662
oct17057315764013251
92518168255117858
10531023042451113
111442226757a3343
124b6839a65a2575
1319a3c347ba2014
14951b91c22c369
15415d1dbd363c8
hex1e2f66fd016a9

531023042451113 has 2 divisors, whose sum is σ = 531023042451114. Its totient is φ = 531023042451112.

The previous prime is 531023042451089. The next prime is 531023042451149. The reversal of 531023042451113 is 311154240320135.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 371521500161449 + 159501542289664 = 19274893^2 + 12629392^2 .

It is a cyclic number.

It is not a de Polignac number, because 531023042451113 - 224 = 531023025673897 is a prime.

It is a super-2 number, since 2×5310230424511132 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (531023042451163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265511521225556 + 265511521225557.

It is an arithmetic number, because the mean of its divisors is an integer number (265511521225557).

Almost surely, 2531023042451113 is an apocalyptic number.

It is an amenable number.

531023042451113 is a deficient number, since it is larger than the sum of its proper divisors (1).

531023042451113 is an equidigital number, since it uses as much as digits as its factorization.

531023042451113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 43200, while the sum is 35.

Adding to 531023042451113 its reverse (311154240320135), we get a palindrome (842177282771248).

The spelling of 531023042451113 in words is "five hundred thirty-one trillion, twenty-three billion, forty-two million, four hundred fifty-one thousand, one hundred thirteen".