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53102411981 = 173123671293
BaseRepresentation
bin110001011101001001…
…101000000011001101
312002001210120000210022
4301131021220003031
51332223204140411
640221144551525
73556633024433
oct613511500315
9162053500708
1053102411981
112057aa220a3
12a35ba825a5
135013730868
1427da794d53
1515abe17edb
hexc5d2680cd

53102411981 has 4 divisors (see below), whose sum is σ = 56226083292. Its totient is φ = 49978740672.

The previous prime is 53102411927. The next prime is 53102411987. The reversal of 53102411981 is 18911420135.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 37742775625 + 15359636356 = 194275^2 + 123934^2 .

It is a cyclic number.

It is not a de Polignac number, because 53102411981 - 222 = 53098217677 is a prime.

It is a super-2 number, since 2×531024119812 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53102411987) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1561835630 + ... + 1561835663.

It is an arithmetic number, because the mean of its divisors is an integer number (14056520823).

Almost surely, 253102411981 is an apocalyptic number.

It is an amenable number.

53102411981 is a deficient number, since it is larger than the sum of its proper divisors (3123671311).

53102411981 is a wasteful number, since it uses less digits than its factorization.

53102411981 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3123671310.

The product of its (nonzero) digits is 8640, while the sum is 35.

The spelling of 53102411981 in words is "fifty-three billion, one hundred two million, four hundred eleven thousand, nine hundred eighty-one".

Divisors: 1 17 3123671293 53102411981