Base | Representation |
---|---|
bin | 11000001001100000100111… |
… | …11111010010001010111111 |
3 | 20222000121221001022022221110 |
4 | 30010300103333102022333 |
5 | 23430021040104114401 |
6 | 304535154014133103 |
7 | 14120405356630506 |
oct | 1404602377221277 |
9 | 228017831268843 |
10 | 53103311004351 |
11 | 15a13a957304a3 |
12 | 5b5793b4b1193 |
13 | 238280b9c868a |
14 | d182dd1a383d |
15 | 6215141169d6 |
hex | 304c13fd22bf |
53103311004351 has 8 divisors (see below), whose sum is σ = 70804467094320. Its totient is φ = 35402181125312.
The previous prime is 53103311004323. The next prime is 53103311004361. The reversal of 53103311004351 is 15340011330135.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 53103311004351 - 245 = 17918938915519 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53103311004361) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1200990 + ... + 10375403.
It is an arithmetic number, because the mean of its divisors is an integer number (8850558386790).
Almost surely, 253103311004351 is an apocalyptic number.
53103311004351 is a deficient number, since it is larger than the sum of its proper divisors (17701156089969).
53103311004351 is a wasteful number, since it uses less digits than its factorization.
53103311004351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13105465.
The product of its (nonzero) digits is 8100, while the sum is 30.
Adding to 53103311004351 its reverse (15340011330135), we get a palindrome (68443322334486).
The spelling of 53103311004351 in words is "fifty-three trillion, one hundred three billion, three hundred eleven million, four thousand, three hundred fifty-one".
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