Base | Representation |
---|---|
bin | 110001011101010000… |
… | …001111001011001011 |
3 | 12002001220211002011212 |
4 | 301131100033023023 |
5 | 1332224130120344 |
6 | 40221250043335 |
7 | 3556653533315 |
oct | 613520171313 |
9 | 162056732155 |
10 | 53104145099 |
11 | 205809a6225 |
12 | a36057954b |
13 | 5013bb9685 |
14 | 27daac67b5 |
15 | 15ac15b79e |
hex | c5d40f2cb |
53104145099 has 2 divisors, whose sum is σ = 53104145100. Its totient is φ = 53104145098.
The previous prime is 53104145077. The next prime is 53104145111. The reversal of 53104145099 is 99054140135.
53104145099 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53104145099 - 228 = 52835709643 is a prime.
It is not a weakly prime, because it can be changed into another prime (53104142099) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26552072549 + 26552072550.
It is an arithmetic number, because the mean of its divisors is an integer number (26552072550).
Almost surely, 253104145099 is an apocalyptic number.
53104145099 is a deficient number, since it is larger than the sum of its proper divisors (1).
53104145099 is an equidigital number, since it uses as much as digits as its factorization.
53104145099 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 97200, while the sum is 41.
The spelling of 53104145099 in words is "fifty-three billion, one hundred four million, one hundred forty-five thousand, ninety-nine".
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