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53104211 is a prime number
BaseRepresentation
bin1100101010010…
…0111001010011
310200220222021122
43022210321103
5102043313321
65134112455
71213243526
oct312447123
9120828248
1053104211
1127a80a86
121594b72b
13b004314
1470a4bbd
1549de8ab
hex32a4e53

53104211 has 2 divisors, whose sum is σ = 53104212. Its totient is φ = 53104210.

The previous prime is 53104193. The next prime is 53104231. The reversal of 53104211 is 11240135.

53104211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 53104211 - 218 = 52842067 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 53104211.

It is not a weakly prime, because it can be changed into another prime (53104231) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26552105 + 26552106.

It is an arithmetic number, because the mean of its divisors is an integer number (26552106).

Almost surely, 253104211 is an apocalyptic number.

53104211 is a deficient number, since it is larger than the sum of its proper divisors (1).

53104211 is an equidigital number, since it uses as much as digits as its factorization.

53104211 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 53104211 is about 7287.2636153772. The cubic root of 53104211 is about 375.8746068780.

Adding to 53104211 its reverse (11240135), we get a palindrome (64344346).

The spelling of 53104211 in words is "fifty-three million, one hundred four thousand, two hundred eleven".