Base | Representation |
---|---|
bin | 1111011101001001010… |
… | …01011101100111011100 |
3 | 1212202201022200020221101 |
4 | 13232210221131213130 |
5 | 32200034041410134 |
6 | 1043542525042444 |
7 | 53236514441422 |
oct | 7564451354734 |
9 | 1782638606841 |
10 | 531043310044 |
11 | 19523a116835 |
12 | 86b053b6424 |
13 | 3b1007053a0 |
14 | 1b9ba051112 |
15 | dc31145e14 |
hex | 7ba4a5d9dc |
531043310044 has 12 divisors (see below), whose sum is σ = 1000812392104. Its totient is φ = 245096912304.
The previous prime is 531043310011. The next prime is 531043310093. The reversal of 531043310044 is 440013340135.
It is a super-2 number, since 2×5310433100442 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 531043309994 and 531043310021.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5106185622 + ... + 5106185725.
Almost surely, 2531043310044 is an apocalyptic number.
It is an amenable number.
531043310044 is a deficient number, since it is larger than the sum of its proper divisors (469769082060).
531043310044 is a wasteful number, since it uses less digits than its factorization.
531043310044 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10212371364 (or 10212371362 counting only the distinct ones).
The product of its (nonzero) digits is 8640, while the sum is 28.
Adding to 531043310044 its reverse (440013340135), we get a palindrome (971056650179).
The spelling of 531043310044 in words is "five hundred thirty-one billion, forty-three million, three hundred ten thousand, forty-four".
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