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53105070314 = 226552535157
BaseRepresentation
bin110001011101010011…
…110001000011101010
312002001222120002100002
4301131103301003222
51332224344222224
640221321543002
73556664435612
oct613523610352
9162058502302
1053105070314
112058147836a
12a360944a62
13501415183a
1427dac87a42
1515ac2909ae
hexc5d4f10ea

53105070314 has 4 divisors (see below), whose sum is σ = 79657605474. Its totient is φ = 26552535156.

The previous prime is 53105070313. The next prime is 53105070331. The reversal of 53105070314 is 41307050135.

53105070314 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 47217117025 + 5887953289 = 217295^2 + 76733^2 .

It is not an unprimeable number, because it can be changed into a prime (53105070313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13276267577 + ... + 13276267580.

Almost surely, 253105070314 is an apocalyptic number.

53105070314 is a deficient number, since it is larger than the sum of its proper divisors (26552535160).

53105070314 is a wasteful number, since it uses less digits than its factorization.

53105070314 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26552535159.

The product of its (nonzero) digits is 6300, while the sum is 29.

The spelling of 53105070314 in words is "fifty-three billion, one hundred five million, seventy thousand, three hundred fourteen".

Divisors: 1 2 26552535157 53105070314