Base | Representation |
---|---|
bin | 110001011101010011… |
… | …110001000011101011 |
3 | 12002001222120002100010 |
4 | 301131103301003223 |
5 | 1332224344222230 |
6 | 40221321543003 |
7 | 3556664435613 |
oct | 613523610353 |
9 | 162058502303 |
10 | 53105070315 |
11 | 20581478370 |
12 | a360944a63 |
13 | 501415183b |
14 | 27dac87a43 |
15 | 15ac2909b0 |
hex | c5d4f10eb |
53105070315 has 32 divisors (see below), whose sum is σ = 92710086912. Its totient is φ = 25743024000.
The previous prime is 53105070313. The next prime is 53105070331. The reversal of 53105070315 is 51307050135.
It is not a de Polignac number, because 53105070315 - 21 = 53105070313 is a prime.
It is a super-2 number, since 2×531050703152 (a number of 22 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (53105070313) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 932820 + ... + 988110.
It is an arithmetic number, because the mean of its divisors is an integer number (2897190216).
Almost surely, 253105070315 is an apocalyptic number.
53105070315 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53105070315 is a deficient number, since it is larger than the sum of its proper divisors (39605016597).
53105070315 is a wasteful number, since it uses less digits than its factorization.
53105070315 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 61131.
The product of its (nonzero) digits is 7875, while the sum is 30.
The spelling of 53105070315 in words is "fifty-three billion, one hundred five million, seventy thousand, three hundred fifteen".
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