Base | Representation |
---|---|
bin | 100110101001000010110… |
… | …1110011001010110010001 |
3 | 200210201011101122002222110 |
4 | 1031102011232121112101 |
5 | 1144003031204010113 |
6 | 15143431454255533 |
7 | 1055460101414250 |
oct | 115220556312621 |
9 | 20721141562873 |
10 | 5310823110033 |
11 | 17683422135a1 |
12 | 719333ab75a9 |
13 | 2c6a6829509c |
14 | 14508c0b0797 |
15 | 9323017cbc3 |
hex | 4d485b99591 |
5310823110033 has 16 divisors (see below), whose sum is σ = 8093445699456. Its totient is φ = 3034469988480.
The previous prime is 5310823110031. The next prime is 5310823110079. The reversal of 5310823110033 is 3300113280135.
5310823110033 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 5310823110033 - 21 = 5310823110031 is a prime.
It is a super-2 number, since 2×53108231100332 (a number of 26 digits) contains 22 as substring.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (5310823110031) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11691588 + ... + 12137333.
It is an arithmetic number, because the mean of its divisors is an integer number (505840356216).
Almost surely, 25310823110033 is an apocalyptic number.
It is an amenable number.
5310823110033 is a deficient number, since it is larger than the sum of its proper divisors (2782622589423).
5310823110033 is a wasteful number, since it uses less digits than its factorization.
5310823110033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23839544.
The product of its (nonzero) digits is 6480, while the sum is 30.
Adding to 5310823110033 its reverse (3300113280135), we get a palindrome (8610936390168).
The spelling of 5310823110033 in words is "five trillion, three hundred ten billion, eight hundred twenty-three million, one hundred ten thousand, thirty-three".
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