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5311003304977 is a prime number
BaseRepresentation
bin100110101001001000001…
…1101110010010000010001
3200210201121221200221222021
41031102100131302100101
51144003413321224402
615143501412411441
71055464420144036
oct115222035622021
920721557627867
105311003304977
1117684249a9737
12719384316b81
132c6a96706906
141450a7db938d
1593240dc3d37
hex4d490772411

5311003304977 has 2 divisors, whose sum is σ = 5311003304978. Its totient is φ = 5311003304976.

The previous prime is 5311003304909. The next prime is 5311003305017. The reversal of 5311003304977 is 7794033001135.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4231397105296 + 1079606199681 = 2057036^2 + 1039041^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5311003304977 is a prime.

It is a super-2 number, since 2×53110033049772 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (5311003301977) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2655501652488 + 2655501652489.

It is an arithmetic number, because the mean of its divisors is an integer number (2655501652489).

Almost surely, 25311003304977 is an apocalyptic number.

It is an amenable number.

5311003304977 is a deficient number, since it is larger than the sum of its proper divisors (1).

5311003304977 is an equidigital number, since it uses as much as digits as its factorization.

5311003304977 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 238140, while the sum is 43.

The spelling of 5311003304977 in words is "five trillion, three hundred eleven billion, three million, three hundred four thousand, nine hundred seventy-seven".