Base | Representation |
---|---|
bin | 100110101001001000100… |
… | …1010100101101110000010 |
3 | 200210201122202210200021100 |
4 | 1031102101022211232002 |
5 | 1144003424323100424 |
6 | 15143502512235230 |
7 | 1055464622032314 |
oct | 115222112455602 |
9 | 20721582720240 |
10 | 5311015050114 |
11 | 17684305a0a64 |
12 | 71938823bb16 |
13 | 2c6a98c898b7 |
14 | 1450a97957b4 |
15 | 93241e43dc9 |
hex | 4d4912a5b82 |
5311015050114 has 24 divisors (see below), whose sum is σ = 11510187532272. Its totient is φ = 1769878618200.
The previous prime is 5311015050109. The next prime is 5311015050151. The reversal of 5311015050114 is 4110505101135.
5311015050114 is a `hidden beast` number, since 5 + 3 + 1 + 1 + 0 + 150 + 501 + 1 + 4 = 666.
It is a super-3 number, since 3×53110150501143 (a number of 39 digits) contains 333 as substring.
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 38239744 + ... + 38378379.
It is an arithmetic number, because the mean of its divisors is an integer number (479591147178).
Almost surely, 25311015050114 is an apocalyptic number.
5311015050114 is an abundant number, since it is smaller than the sum of its proper divisors (6199172482158).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5311015050114 is a wasteful number, since it uses less digits than its factorization.
5311015050114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 76621982 (or 76621979 counting only the distinct ones).
The product of its (nonzero) digits is 1500, while the sum is 27.
The spelling of 5311015050114 in words is "five trillion, three hundred eleven billion, fifteen million, fifty thousand, one hundred fourteen".
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