Search a number
-
+
531104445704377 is a prime number
BaseRepresentation
bin111100011000010010110001…
…1110100110010100010111001
32120122111002101222201100120001
41320300211203310302202321
51024103103401100020002
65121322003013233001
7216604013162213656
oct17060454364624271
92518432358640501
10531104445704377
11144254148810366
124b697724332761
1319a46c1b9542bc
1495218414c4c2d
1541603a35dda87
hex1e30963d328b9

531104445704377 has 2 divisors, whose sum is σ = 531104445704378. Its totient is φ = 531104445704376.

The previous prime is 531104445704317. The next prime is 531104445704419. The reversal of 531104445704377 is 773407544401135.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 416484382386601 + 114620063317776 = 20407949^2 + 10706076^2 .

It is a cyclic number.

It is not a de Polignac number, because 531104445704377 - 243 = 522308352682169 is a prime.

It is not a weakly prime, because it can be changed into another prime (531104445704317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265552222852188 + 265552222852189.

It is an arithmetic number, because the mean of its divisors is an integer number (265552222852189).

Almost surely, 2531104445704377 is an apocalyptic number.

It is an amenable number.

531104445704377 is a deficient number, since it is larger than the sum of its proper divisors (1).

531104445704377 is an equidigital number, since it uses as much as digits as its factorization.

531104445704377 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 19756800, while the sum is 55.

The spelling of 531104445704377 in words is "five hundred thirty-one trillion, one hundred four billion, four hundred forty-five million, seven hundred four thousand, three hundred seventy-seven".