531111234013 has 4 divisors (see below), whose sum is σ = 531299640960. Its totient is φ = 530922827068.

The previous prime is 531111234011. The next prime is 531111234019. The reversal of 531111234013 is 310432111135.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 531111234013 - 2¹ = 531111234011 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (531111234011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 94199245 + ... + 94204882.

It is an arithmetic number, because the mean of its divisors is an integer number (132824910240).

Almost surely, 2^531111234013 is an apocalyptic number.

It is an amenable number.

531111234013 is a deficient number, since it is larger than the sum of its proper divisors (188406947).

531111234013 is a wasteful number, since it uses less digits than its factorization.

531111234013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 188406946.

The product of its (nonzero) digits is 1080, while the sum is 25.

Adding to 531111234013 its reverse (310432111135), we get a palindrome (841543345148).

The spelling of 531111234013 in words is "five hundred thirty-one billion, one hundred eleven million, two hundred thirty-four thousand, thirteen".