Base | Representation |
---|---|
bin | 11000001001110001000001… |
… | …00100110100001001001111 |
3 | 20222001110122102010111222200 |
4 | 30010320200210310021033 |
5 | 23430142101144312030 |
6 | 304543211212212543 |
7 | 14121136436014266 |
oct | 1404704044641117 |
9 | 228043572114880 |
10 | 53112112104015 |
11 | 15a177a171a988 |
12 | 5b59596a6a153 |
13 | 23835b21b8063 |
14 | d188d60015dd |
15 | 62187bb04d60 |
hex | 304e2093424f |
53112112104015 has 48 divisors (see below), whose sum is σ = 92148406240800. Its totient is φ = 28299567062016.
The previous prime is 53112112103969. The next prime is 53112112104017. The reversal of 53112112104015 is 51040121121135.
53112112104015 is a `hidden beast` number, since 5 + 31 + 1 + 2 + 11 + 210 + 401 + 5 = 666.
It is not a de Polignac number, because 53112112104015 - 27 = 53112112103887 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 53112112104015.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53112112104017) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1287327267 + ... + 1287368523.
It is an arithmetic number, because the mean of its divisors is an integer number (1919758463350).
Almost surely, 253112112104015 is an apocalyptic number.
53112112104015 is a deficient number, since it is larger than the sum of its proper divisors (39036294136785).
53112112104015 is a wasteful number, since it uses less digits than its factorization.
53112112104015 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 67736 (or 67733 counting only the distinct ones).
The product of its (nonzero) digits is 1200, while the sum is 27.
The spelling of 53112112104015 in words is "fifty-three trillion, one hundred twelve billion, one hundred twelve million, one hundred four thousand, fifteen".
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