Base | Representation |
---|---|
bin | 1001111001001010… |
… | …01010001001000101 |
3 | 111201011020002021222 |
4 | 10330211022021011 |
5 | 41334200404000 |
6 | 2235012250125 |
7 | 245422440356 |
oct | 47445121105 |
9 | 14634202258 |
10 | 5311341125 |
11 | 2286128222 |
12 | 1042910945 |
13 | 6684ca7cc |
14 | 385587d2d |
15 | 211455a85 |
hex | 13c94a245 |
5311341125 has 16 divisors (see below), whose sum is σ = 6916755456. Its totient is φ = 4064328400.
The previous prime is 5311341107. The next prime is 5311341131. The reversal of 5311341125 is 5211431135.
5311341125 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 5311341125 - 28 = 5311340869 is a prime.
It is a super-2 number, since 2×53113411252 = 56420689092232531250, which contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5311341094 and 5311341103.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 920837 + ... + 926586.
It is an arithmetic number, because the mean of its divisors is an integer number (432297216).
Almost surely, 25311341125 is an apocalyptic number.
It is an amenable number.
5311341125 is a deficient number, since it is larger than the sum of its proper divisors (1605414331).
5311341125 is a wasteful number, since it uses less digits than its factorization.
5311341125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1847461 (or 1847451 counting only the distinct ones).
The product of its digits is 1800, while the sum is 26.
The square root of 5311341125 is about 72878.9484350591. The cubic root of 5311341125 is about 1744.7561255561.
The spelling of 5311341125 in words is "five billion, three hundred eleven million, three hundred forty-one thousand, one hundred twenty-five".
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