Base | Representation |
---|---|
bin | 11000001001110011011110… |
… | …10101010001110001011111 |
3 | 20222001121001111102220001011 |
4 | 30010321233111101301133 |
5 | 23430202302424244020 |
6 | 304543550253000051 |
7 | 14121214252062040 |
oct | 1404715725216137 |
9 | 228047044386034 |
10 | 53113433431135 |
11 | 15a1830a564570 |
12 | 5b598a5483027 |
13 | 2383762b7c51c |
14 | d189bd6b48c7 |
15 | 621907b0935a |
hex | 304e6f551c5f |
53113433431135 has 64 divisors (see below), whose sum is σ = 80936251812864. Its totient is φ = 32499424742400.
The previous prime is 53113433431099. The next prime is 53113433431147.
53113433431135 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 53113433431135 - 221 = 53113431333983 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3584589 + ... + 10912201.
It is an arithmetic number, because the mean of its divisors is an integer number (1264628934576).
Almost surely, 253113433431135 is an apocalyptic number.
53113433431135 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53113433431135 is a deficient number, since it is larger than the sum of its proper divisors (27822818381729).
53113433431135 is a wasteful number, since it uses less digits than its factorization.
53113433431135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7327984.
The product of its digits is 291600, while the sum is 40.
It can be divided in two parts, 5311343 and 3431135, that added together give a palindrome (8742478).
The spelling of 53113433431135 in words is "fifty-three trillion, one hundred thirteen billion, four hundred thirty-three million, four hundred thirty-one thousand, one hundred thirty-five".
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