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53114404434 = 2371397279129
BaseRepresentation
bin110001011101110111…
…010111111001010010
312002002122010022100020
4301131313113321102
51332234241420214
640222254004310
73560136663030
oct613567277122
9162078108306
1053114404434
1120586773213
12a363aa6696
13501606c2a0
1427dc1d7550
1515aced64a9
hexc5ddd7e52

53114404434 has 32 divisors (see below), whose sum is σ = 130743150720. Its totient is φ = 14008194432.

The previous prime is 53114404379. The next prime is 53114404451. The reversal of 53114404434 is 43440441135.

It is a super-2 number, since 2×531144044342 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 53114404395 and 53114404404.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 48639019 + ... + 48640110.

It is an arithmetic number, because the mean of its divisors is an integer number (4085723460).

Almost surely, 253114404434 is an apocalyptic number.

53114404434 is an abundant number, since it is smaller than the sum of its proper divisors (77628746286).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

53114404434 is a wasteful number, since it uses less digits than its factorization.

53114404434 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 97279154.

The product of its (nonzero) digits is 46080, while the sum is 33.

Adding to 53114404434 its reverse (43440441135), we get a palindrome (96554845569).

The spelling of 53114404434 in words is "fifty-three billion, one hundred fourteen million, four hundred four thousand, four hundred thirty-four".

Divisors: 1 2 3 6 7 13 14 21 26 39 42 78 91 182 273 546 97279129 194558258 291837387 583674774 680953903 1264628677 1361907806 2042861709 2529257354 3793886031 4085723418 7587772062 8852400739 17704801478 26557202217 53114404434