Search a number
-
+
53117614374000 = 243531110149116229
BaseRepresentation
bin11000001001111011010001…
…00010010011110001110000
320222001222211212121210102220
430010331220202103301300
523430234333234432000
6304545521205041040
714121423000361611
oct1404755042236160
9228058755553386
1053117614374000
1115a1a0655a4850
125b5a6716b6180
132383c7b115007
14d18c98a89c08
15621a9ebc21a0
hex304f68893c70

53117614374000 has 640 divisors, whose sum is σ = 189065080488960. Its totient is φ = 12722752000000.

The previous prime is 53117614373981. The next prime is 53117614374017. The reversal of 53117614374000 is 47341671135.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 3272997886 + ... + 3273014114.

It is an arithmetic number, because the mean of its divisors is an integer number (295414188264).

Almost surely, 253117614374000 is an apocalyptic number.

53117614374000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 53117614374000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (94532540244480).

53117614374000 is an abundant number, since it is smaller than the sum of its proper divisors (135947466114960).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

53117614374000 is a wasteful number, since it uses less digits than its factorization.

53117614374000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16858 (or 16842 counting only the distinct ones).

The product of its (nonzero) digits is 211680, while the sum is 42.

The spelling of 53117614374000 in words is "fifty-three trillion, one hundred seventeen billion, six hundred fourteen million, three hundred seventy-four thousand".