Base | Representation |
---|---|
bin | 1001111001001111… |
… | …01110011110101001 |
3 | 111201012111021122111 |
4 | 10330213232132221 |
5 | 41334333423444 |
6 | 2235034522321 |
7 | 245431243003 |
oct | 47447563651 |
9 | 14635437574 |
10 | 5312014249 |
11 | 2286547a23 |
12 | 1042b963a1 |
13 | 6686a4cc9 |
14 | 3856c1373 |
15 | 21153a234 |
hex | 13c9ee7a9 |
5312014249 has 2 divisors, whose sum is σ = 5312014250. Its totient is φ = 5312014248.
The previous prime is 5312014241. The next prime is 5312014333. The reversal of 5312014249 is 9424102135.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3893136025 + 1418878224 = 62395^2 + 37668^2 .
It is a cyclic number.
It is not a de Polignac number, because 5312014249 - 23 = 5312014241 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5312014249.
It is not a weakly prime, because it can be changed into another prime (5312014241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2656007124 + 2656007125.
It is an arithmetic number, because the mean of its divisors is an integer number (2656007125).
Almost surely, 25312014249 is an apocalyptic number.
It is an amenable number.
5312014249 is a deficient number, since it is larger than the sum of its proper divisors (1).
5312014249 is an equidigital number, since it uses as much as digits as its factorization.
5312014249 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 31.
The square root of 5312014249 is about 72883.5663850226. The cubic root of 5312014249 is about 1744.8298286996.
The spelling of 5312014249 in words is "five billion, three hundred twelve million, fourteen thousand, two hundred forty-nine".
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