Base | Representation |
---|---|
bin | 1111011101011100011… |
… | …00001100111010111010 |
3 | 1212210010110221021001012 |
4 | 13232232030030322322 |
5 | 32200401033133032 |
6 | 1044010444353522 |
7 | 53243500333061 |
oct | 7565614147272 |
9 | 1783113837035 |
10 | 531203411642 |
11 | 195311528502 |
12 | 86b4ab458a2 |
13 | 3b127930167 |
14 | 1b9d34091d8 |
15 | dc4021d6b2 |
hex | 7bae30ceba |
531203411642 has 8 divisors (see below), whose sum is σ = 802537528800. Its totient is φ = 263690902044.
The previous prime is 531203411603. The next prime is 531203411677. The reversal of 531203411642 is 246114302135.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×5312034116422 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 531203411599 and 531203411608.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 955401542 + ... + 955402097.
It is an arithmetic number, because the mean of its divisors is an integer number (100317191100).
Almost surely, 2531203411642 is an apocalyptic number.
531203411642 is a deficient number, since it is larger than the sum of its proper divisors (271334117158).
531203411642 is a wasteful number, since it uses less digits than its factorization.
531203411642 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1910803780.
The product of its (nonzero) digits is 17280, while the sum is 32.
Adding to 531203411642 its reverse (246114302135), we get a palindrome (777317713777).
The spelling of 531203411642 in words is "five hundred thirty-one billion, two hundred three million, four hundred eleven thousand, six hundred forty-two".
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