Base | Representation |
---|---|
bin | 11000001010000000101011… |
… | …10010011001101110000111 |
3 | 20222002021100110001021201011 |
4 | 30011000111302121232013 |
5 | 23430311311342113030 |
6 | 304551121441143051 |
7 | 14121555013621615 |
oct | 1405002562315607 |
9 | 228067313037634 |
10 | 53120521051015 |
11 | 15a20317314260 |
12 | 5b5b14302aa87 |
13 | 2384322382c42 |
14 | d19092b1c6b5 |
15 | 621bbee7eb2a |
hex | 305015c99b87 |
53120521051015 has 32 divisors (see below), whose sum is σ = 69592616884224. Its totient is φ = 38603656045440.
The previous prime is 53120521050997. The next prime is 53120521051057. The reversal of 53120521051015 is 51015012502135.
It is not a de Polignac number, because 53120521051015 - 217 = 53120520919943 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 533894602 + ... + 533994088.
It is an arithmetic number, because the mean of its divisors is an integer number (2174769277632).
Almost surely, 253120521051015 is an apocalyptic number.
53120521051015 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53120521051015 is a deficient number, since it is larger than the sum of its proper divisors (16472095833209).
53120521051015 is a wasteful number, since it uses less digits than its factorization.
53120521051015 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 106807.
The product of its (nonzero) digits is 7500, while the sum is 31.
The spelling of 53120521051015 in words is "fifty-three trillion, one hundred twenty billion, five hundred twenty-one million, fifty-one thousand, fifteen".
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