Base | Representation |
---|---|
bin | 100110101001101001101… |
… | …0010010001110111011111 |
3 | 200210211112002011120101102 |
4 | 1031103103102101313133 |
5 | 1144013212314042312 |
6 | 15144204540503315 |
7 | 1055534252031335 |
oct | 115232322216737 |
9 | 20724462146342 |
10 | 5312124362207 |
11 | 176894a796613 |
12 | 71963784ab3b |
13 | 2c6c14a4aca0 |
14 | 145172c39b55 |
15 | 932a9518ec2 |
hex | 4d4d3491ddf |
5312124362207 has 8 divisors (see below), whose sum is σ = 5720966435184. Its totient is φ = 4903313306688.
The previous prime is 5312124362189. The next prime is 5312124362249. The reversal of 5312124362207 is 7022634212135.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5312124362207 - 26 = 5312124362143 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5312124361207) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7398053 + ... + 8084270.
It is an arithmetic number, because the mean of its divisors is an integer number (715120804398).
Almost surely, 25312124362207 is an apocalyptic number.
5312124362207 is a deficient number, since it is larger than the sum of its proper divisors (408842072977).
5312124362207 is a wasteful number, since it uses less digits than its factorization.
5312124362207 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15508729.
The product of its (nonzero) digits is 120960, while the sum is 38.
The spelling of 5312124362207 in words is "five trillion, three hundred twelve billion, one hundred twenty-four million, three hundred sixty-two thousand, two hundred seven".
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