Base | Representation |
---|---|
bin | 111100011001000101011110… |
… | …0000011111100010110110100 |
3 | 2120122212111101020202102120222 |
4 | 1320302022330003330112310 |
5 | 1024111344314331113012 |
6 | 5121444004324113512 |
7 | 216614615534503226 |
oct | 17062127403742664 |
9 | 2518774336672528 |
10 | 531213300254132 |
11 | 144296328322781 |
12 | 4b6b4843535898 |
13 | 19a54278a48ca2 |
14 | 9526c0a4d8416 |
15 | 4163124d73972 |
hex | 1e322bc0fc5b4 |
531213300254132 has 12 divisors (see below), whose sum is σ = 929623776156096. Its totient is φ = 265606507066680.
The previous prime is 531213300254111. The next prime is 531213300254141. The reversal of 531213300254132 is 231452003312135.
It is a super-3 number, since 3×5312133002541323 (a number of 45 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 531213300254092 and 531213300254101.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27181478 + ... + 42441245.
It is an arithmetic number, because the mean of its divisors is an integer number (77468648013008).
Almost surely, 2531213300254132 is an apocalyptic number.
It is an amenable number.
531213300254132 is a deficient number, since it is larger than the sum of its proper divisors (398410475901964).
531213300254132 is a wasteful number, since it uses less digits than its factorization.
531213300254132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 71530198 (or 71530196 counting only the distinct ones).
The product of its (nonzero) digits is 64800, while the sum is 35.
Adding to 531213300254132 its reverse (231452003312135), we get a palindrome (762665303566267).
The spelling of 531213300254132 in words is "five hundred thirty-one trillion, two hundred thirteen billion, three hundred million, two hundred fifty-four thousand, one hundred thirty-two".
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