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53121433481 is a prime number
BaseRepresentation
bin110001011110010010…
…001011111110001001
312002010010100102101022
4301132102023332021
51332243041332411
640223104402225
73560253506624
oct613622137611
9162103312338
1053121433481
112058a734246
12a366316375
13501766079c
1427dd106dbb
1515ad923edb
hexc5e48bf89

53121433481 has 2 divisors, whose sum is σ = 53121433482. Its totient is φ = 53121433480.

The previous prime is 53121433433. The next prime is 53121433507. The reversal of 53121433481 is 18433412135.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 26937015625 + 26184417856 = 164125^2 + 161816^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53121433481 is a prime.

It is a super-2 number, since 2×531214334812 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (53121433681) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26560716740 + 26560716741.

It is an arithmetic number, because the mean of its divisors is an integer number (26560716741).

Almost surely, 253121433481 is an apocalyptic number.

It is an amenable number.

53121433481 is a deficient number, since it is larger than the sum of its proper divisors (1).

53121433481 is an equidigital number, since it uses as much as digits as its factorization.

53121433481 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 34560, while the sum is 35.

The spelling of 53121433481 in words is "fifty-three billion, one hundred twenty-one million, four hundred thirty-three thousand, four hundred eighty-one".