Base | Representation |
---|---|
bin | 111100011001001001001001… |
… | …1101001110010110000001001 |
3 | 2120122220020210122120012122211 |
4 | 1320302102103221302300021 |
5 | 1024112012020313320001 |
6 | 5121451353401345121 |
7 | 216615315566352055 |
oct | 17062222351626011 |
9 | 2518806718505584 |
10 | 531221212245001 |
11 | 144299718449603 |
12 | 4b6b62911981a1 |
13 | 19a54c39c863a5 |
14 | 952735b212c65 |
15 | 4163439787351 |
hex | 1e32493a72c09 |
531221212245001 has 2 divisors, whose sum is σ = 531221212245002. Its totient is φ = 531221212245000.
The previous prime is 531221212244903. The next prime is 531221212245007. The reversal of 531221212245001 is 100542212122135.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 359992184371600 + 171229027873401 = 18973460^2 + 13085451^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-531221212245001 is a prime.
It is not a weakly prime, because it can be changed into another prime (531221212245007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265610606122500 + 265610606122501.
It is an arithmetic number, because the mean of its divisors is an integer number (265610606122501).
Almost surely, 2531221212245001 is an apocalyptic number.
It is an amenable number.
531221212245001 is a deficient number, since it is larger than the sum of its proper divisors (1).
531221212245001 is an equidigital number, since it uses as much as digits as its factorization.
531221212245001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9600, while the sum is 31.
Adding to 531221212245001 its reverse (100542212122135), we get a palindrome (631763424367136).
The spelling of 531221212245001 in words is "five hundred thirty-one trillion, two hundred twenty-one billion, two hundred twelve million, two hundred forty-five thousand, one".
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