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531221212245001 is a prime number
BaseRepresentation
bin111100011001001001001001…
…1101001110010110000001001
32120122220020210122120012122211
41320302102103221302300021
51024112012020313320001
65121451353401345121
7216615315566352055
oct17062222351626011
92518806718505584
10531221212245001
11144299718449603
124b6b62911981a1
1319a54c39c863a5
14952735b212c65
154163439787351
hex1e32493a72c09

531221212245001 has 2 divisors, whose sum is σ = 531221212245002. Its totient is φ = 531221212245000.

The previous prime is 531221212244903. The next prime is 531221212245007. The reversal of 531221212245001 is 100542212122135.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 359992184371600 + 171229027873401 = 18973460^2 + 13085451^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-531221212245001 is a prime.

It is not a weakly prime, because it can be changed into another prime (531221212245007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265610606122500 + 265610606122501.

It is an arithmetic number, because the mean of its divisors is an integer number (265610606122501).

Almost surely, 2531221212245001 is an apocalyptic number.

It is an amenable number.

531221212245001 is a deficient number, since it is larger than the sum of its proper divisors (1).

531221212245001 is an equidigital number, since it uses as much as digits as its factorization.

531221212245001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9600, while the sum is 31.

Adding to 531221212245001 its reverse (100542212122135), we get a palindrome (631763424367136).

The spelling of 531221212245001 in words is "five hundred thirty-one trillion, two hundred twenty-one billion, two hundred twelve million, two hundred forty-five thousand, one".