Base | Representation |
---|---|
bin | 11000001010000011110101… |
… | …00001111001001001110111 |
3 | 20222002102201020101212121112 |
4 | 30011001322201321021313 |
5 | 23430323242033102020 |
6 | 304552001255305235 |
7 | 14121644626056326 |
oct | 1405017241711167 |
9 | 228072636355545 |
10 | 53122211222135 |
11 | 15a210043838a0 |
12 | 5b5b53507b21b |
13 | 238453159a7b3 |
14 | d191b33a60bd |
15 | 621c6d5412c5 |
hex | 30507a879277 |
53122211222135 has 8 divisors (see below), whose sum is σ = 69541803781776. Its totient is φ = 38634335434240.
The previous prime is 53122211222089. The next prime is 53122211222149.
53122211222135 is nontrivially palindromic in base 10.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 53122211222135 - 244 = 35530025177719 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 482929192874 + ... + 482929192983.
It is an arithmetic number, because the mean of its divisors is an integer number (8692725472722).
Almost surely, 253122211222135 is an apocalyptic number.
53122211222135 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53122211222135 is a deficient number, since it is larger than the sum of its proper divisors (16419592559641).
53122211222135 is a wasteful number, since it uses less digits than its factorization.
53122211222135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 965858385873.
The product of its digits is 14400, while the sum is 32.
It can be divided in two parts, 5312221 and 1222135, that added together give a palindrome (6534356).
The spelling of 53122211222135 in words is "fifty-three trillion, one hundred twenty-two billion, two hundred eleven million, two hundred twenty-two thousand, one hundred thirty-five".
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