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53122345033 is a prime number
BaseRepresentation
bin110001011110010101…
…101010100001001001
312002010012001201210111
4301132111222201021
51332243310020113
640223140114321
73560264324332
oct613625524111
9162105051714
1053122345033
11205901a709a
12a3666959a1
1350178bc674
1427dd2a3289
1515ada5413d
hexc5e56a849

53122345033 has 2 divisors, whose sum is σ = 53122345034. Its totient is φ = 53122345032.

The previous prime is 53122344941. The next prime is 53122345049. The reversal of 53122345033 is 33054322135.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 42853968144 + 10268376889 = 207012^2 + 101333^2 .

It is a cyclic number.

It is not a de Polignac number, because 53122345033 - 29 = 53122344521 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 53122344986 and 53122345004.

It is not a weakly prime, because it can be changed into another prime (53122345733) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26561172516 + 26561172517.

It is an arithmetic number, because the mean of its divisors is an integer number (26561172517).

Almost surely, 253122345033 is an apocalyptic number.

It is an amenable number.

53122345033 is a deficient number, since it is larger than the sum of its proper divisors (1).

53122345033 is an equidigital number, since it uses as much as digits as its factorization.

53122345033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32400, while the sum is 31.

Adding to 53122345033 its reverse (33054322135), we get a palindrome (86176667168).

The spelling of 53122345033 in words is "fifty-three billion, one hundred twenty-two million, three hundred forty-five thousand, thirty-three".