Base | Representation |
---|---|
bin | 1111011101011110110… |
… | …11001011000100000011 |
3 | 1212210011220220000112101 |
4 | 13232233123023010003 |
5 | 32200421333112121 |
6 | 1044012504211231 |
7 | 53244141314065 |
oct | 7565733130403 |
9 | 1783156800471 |
10 | 531224113411 |
11 | 195322188002 |
12 | 86b55a69b17 |
13 | 3b12bccab24 |
14 | 1b9d6077735 |
15 | dc41e5c491 |
hex | 7baf6cb103 |
531224113411 has 2 divisors, whose sum is σ = 531224113412. Its totient is φ = 531224113410.
The previous prime is 531224113379. The next prime is 531224113421. The reversal of 531224113411 is 114311422135.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 531224113411 - 25 = 531224113379 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 531224113411.
It is not a weakly prime, because it can be changed into another prime (531224113421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265612056705 + 265612056706.
It is an arithmetic number, because the mean of its divisors is an integer number (265612056706).
Almost surely, 2531224113411 is an apocalyptic number.
531224113411 is a deficient number, since it is larger than the sum of its proper divisors (1).
531224113411 is an equidigital number, since it uses as much as digits as its factorization.
531224113411 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2880, while the sum is 28.
Adding to 531224113411 its reverse (114311422135), we get a palindrome (645535535546).
The spelling of 531224113411 in words is "five hundred thirty-one billion, two hundred twenty-four million, one hundred thirteen thousand, four hundred eleven".
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