53123007433 has 2 divisors, whose sum is σ = 53123007434. Its totient is φ = 53123007432.

The previous prime is 53123007401. The next prime is 53123007449. The reversal of 53123007433 is 33470032135.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 45859365904 + 7263641529 = 214148^2 + 85227^2 .

It is a cyclic number.

It is not a de Polignac number, because 53123007433 - 2⁵ = 53123007401 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 53123007395 and 53123007404.

It is not a weakly prime, because it can be changed into another prime (53123007473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26561503716 + 26561503717.

It is an arithmetic number, because the mean of its divisors is an integer number (26561503717).

Almost surely, 2^53123007433 is an apocalyptic number.

It is an amenable number.

53123007433 is a deficient number, since it is larger than the sum of its proper divisors (1).

53123007433 is an equidigital number, since it uses as much as digits as its factorization.

53123007433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 22680, while the sum is 31.

Adding to 53123007433 its reverse (33470032135), we get a palindrome (86593039568).

The spelling of 53123007433 in words is "fifty-three billion, one hundred twenty-three million, seven thousand, four hundred thirty-three".