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53123104401 = 317707701467
BaseRepresentation
bin110001011110011000…
…100011111010010001
312002010020111022110020
4301132120203322101
51332244003320101
640223204254053
73560303636253
oct613630437221
9162106438406
1053123104401
1120590675674
12a3669a1329
135017ac71b3
1427dd41dcd3
1515adb54136
hexc5e623e91

53123104401 has 4 divisors (see below), whose sum is σ = 70830805872. Its totient is φ = 35415402932.

The previous prime is 53123104387. The next prime is 53123104403. The reversal of 53123104401 is 10440132135.

It is a happy number.

53123104401 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 53123104401 - 27 = 53123104273 is a prime.

It is not an unprimeable number, because it can be changed into a prime (53123104403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8853850731 + ... + 8853850736.

It is an arithmetic number, because the mean of its divisors is an integer number (17707701468).

Almost surely, 253123104401 is an apocalyptic number.

It is an amenable number.

53123104401 is a deficient number, since it is larger than the sum of its proper divisors (17707701471).

53123104401 is a wasteful number, since it uses less digits than its factorization.

53123104401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17707701470.

The product of its (nonzero) digits is 1440, while the sum is 24.

Adding to 53123104401 its reverse (10440132135), we get a palindrome (63563236536).

The spelling of 53123104401 in words is "fifty-three billion, one hundred twenty-three million, one hundred four thousand, four hundred one".

Divisors: 1 3 17707701467 53123104401