Base | Representation |
---|---|
bin | 1111011101100000110… |
… | …11100000110110110001 |
3 | 1212210020002121220222202 |
4 | 13232300123200312301 |
5 | 32200440142324024 |
6 | 1044014305512545 |
7 | 53244434552354 |
oct | 7566033406661 |
9 | 1783202556882 |
10 | 531240979889 |
11 | 195330758044 |
12 | 86b5b642755 |
13 | 3b132654ba9 |
14 | 1b9d83c829b |
15 | dc4368ebae |
hex | 7bb06e0db1 |
531240979889 has 2 divisors, whose sum is σ = 531240979890. Its totient is φ = 531240979888.
The previous prime is 531240979823. The next prime is 531240979909. The reversal of 531240979889 is 988979042135.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 498323046400 + 32917933489 = 705920^2 + 181433^2 .
It is a cyclic number.
It is not a de Polignac number, because 531240979889 - 224 = 531224202673 is a prime.
It is not a weakly prime, because it can be changed into another prime (531240979289) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265620489944 + 265620489945.
It is an arithmetic number, because the mean of its divisors is an integer number (265620489945).
Almost surely, 2531240979889 is an apocalyptic number.
It is an amenable number.
531240979889 is a deficient number, since it is larger than the sum of its proper divisors (1).
531240979889 is an equidigital number, since it uses as much as digits as its factorization.
531240979889 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 39191040, while the sum is 65.
The spelling of 531240979889 in words is "five hundred thirty-one billion, two hundred forty million, nine hundred seventy-nine thousand, eight hundred eighty-nine".
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