Base | Representation |
---|---|
bin | 1111011101100000111… |
… | …00001000001100101001 |
3 | 1212210020002221010001001 |
4 | 13232300130020030221 |
5 | 32200440213003113 |
6 | 1044014313155001 |
7 | 53244436123231 |
oct | 7566034101451 |
9 | 1783202833031 |
10 | 531241141033 |
11 | 195330858119 |
12 | 86b5b6bba61 |
13 | 3b1326b0345 |
14 | 1b9d842acc1 |
15 | dc436c27dd |
hex | 7bb0708329 |
531241141033 has 2 divisors, whose sum is σ = 531241141034. Its totient is φ = 531241141032.
The previous prime is 531241141009. The next prime is 531241141051. The reversal of 531241141033 is 330141142135.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 513813708864 + 17427432169 = 716808^2 + 132013^2 .
It is a cyclic number.
It is not a de Polignac number, because 531241141033 - 217 = 531241009961 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 531241140992 and 531241141010.
It is not a weakly prime, because it can be changed into another prime (531241141003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265620570516 + 265620570517.
It is an arithmetic number, because the mean of its divisors is an integer number (265620570517).
Almost surely, 2531241141033 is an apocalyptic number.
It is an amenable number.
531241141033 is a deficient number, since it is larger than the sum of its proper divisors (1).
531241141033 is an equidigital number, since it uses as much as digits as its factorization.
531241141033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 531241141033 its reverse (330141142135), we get a palindrome (861382283168).
The spelling of 531241141033 in words is "five hundred thirty-one billion, two hundred forty-one million, one hundred forty-one thousand, thirty-three".
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