Search a number
-
+
531244201403 is a prime number
BaseRepresentation
bin1111011101100001001…
…11110011010110111011
31212210020022200121002002
413232300213303112323
532200442003421103
61044014502531215
753244504130466
oct7566047632673
91783208617062
10531244201403
11195332558453
1286b60736b0b
133b133212306
141b9d89c62dd
15dc43ac9488
hex7bb09f35bb

531244201403 has 2 divisors, whose sum is σ = 531244201404. Its totient is φ = 531244201402.

The previous prime is 531244201399. The next prime is 531244201429. The reversal of 531244201403 is 304102442135.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 531244201403 - 22 = 531244201399 is a prime.

It is a super-2 number, since 2×5312442014032 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (531244201493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265622100701 + 265622100702.

It is an arithmetic number, because the mean of its divisors is an integer number (265622100702).

Almost surely, 2531244201403 is an apocalyptic number.

531244201403 is a deficient number, since it is larger than the sum of its proper divisors (1).

531244201403 is an equidigital number, since it uses as much as digits as its factorization.

531244201403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11520, while the sum is 29.

Adding to 531244201403 its reverse (304102442135), we get a palindrome (835346643538).

The spelling of 531244201403 in words is "five hundred thirty-one billion, two hundred forty-four million, two hundred one thousand, four hundred three".