Base | Representation |
---|---|
bin | 1111011101100001001… |
… | …11110011010110111011 |
3 | 1212210020022200121002002 |
4 | 13232300213303112323 |
5 | 32200442003421103 |
6 | 1044014502531215 |
7 | 53244504130466 |
oct | 7566047632673 |
9 | 1783208617062 |
10 | 531244201403 |
11 | 195332558453 |
12 | 86b60736b0b |
13 | 3b133212306 |
14 | 1b9d89c62dd |
15 | dc43ac9488 |
hex | 7bb09f35bb |
531244201403 has 2 divisors, whose sum is σ = 531244201404. Its totient is φ = 531244201402.
The previous prime is 531244201399. The next prime is 531244201429. The reversal of 531244201403 is 304102442135.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 531244201403 - 22 = 531244201399 is a prime.
It is a super-2 number, since 2×5312442014032 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (531244201493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265622100701 + 265622100702.
It is an arithmetic number, because the mean of its divisors is an integer number (265622100702).
Almost surely, 2531244201403 is an apocalyptic number.
531244201403 is a deficient number, since it is larger than the sum of its proper divisors (1).
531244201403 is an equidigital number, since it uses as much as digits as its factorization.
531244201403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11520, while the sum is 29.
Adding to 531244201403 its reverse (304102442135), we get a palindrome (835346643538).
The spelling of 531244201403 in words is "five hundred thirty-one billion, two hundred forty-four million, two hundred one thousand, four hundred three".
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