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53124431101 = 77589204443
BaseRepresentation
bin110001011110011101…
…100111110011111101
312002010022222201100021
4301132131213303331
51332244323243401
640223252532141
73560321133220
oct613635476375
9162108881307
1053124431101
11205913a1415
12a367321051
135018170021
1427dd6875b7
1515add172a1
hexc5e767cfd

53124431101 has 4 divisors (see below), whose sum is σ = 60713635552. Its totient is φ = 45535226652.

The previous prime is 53124431099. The next prime is 53124431123. The reversal of 53124431101 is 10113442135.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10113442135 = 52022688427.

It is a cyclic number.

It is not a de Polignac number, because 53124431101 - 21 = 53124431099 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53124431131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3794602215 + ... + 3794602228.

It is an arithmetic number, because the mean of its divisors is an integer number (15178408888).

Almost surely, 253124431101 is an apocalyptic number.

It is an amenable number.

53124431101 is a deficient number, since it is larger than the sum of its proper divisors (7589204451).

53124431101 is an equidigital number, since it uses as much as digits as its factorization.

53124431101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7589204450.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 53124431101 its reverse (10113442135), we get a palindrome (63237873236).

The spelling of 53124431101 in words is "fifty-three billion, one hundred twenty-four million, four hundred thirty-one thousand, one hundred one".

Divisors: 1 7 7589204443 53124431101