Base | Representation |
---|---|
bin | 11000001010001001100100… |
… | …11100010010000011110111 |
3 | 20222002201200021101101111211 |
4 | 30011010302130102003313 |
5 | 23430401101432242111 |
6 | 304553231401142251 |
7 | 14122114243515610 |
oct | 1405046234220367 |
9 | 228081607341454 |
10 | 53125296759031 |
11 | 15a22348057392 |
12 | 5b6005648a987 |
13 | 2384903900683 |
14 | d193c70b6c07 |
15 | 621d9e37e521 |
hex | 3051327120f7 |
53125296759031 has 4 divisors (see below), whose sum is σ = 60714624867472. Its totient is φ = 45535968650592.
The previous prime is 53125296758983. The next prime is 53125296759047. The reversal of 53125296759031 is 13095769252135.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 53125296759031 - 27 = 53125296758903 is a prime.
It is a super-2 number, since 2×531252967590312 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53125296759061) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3794664054210 + ... + 3794664054223.
It is an arithmetic number, because the mean of its divisors is an integer number (15178656216868).
Almost surely, 253125296759031 is an apocalyptic number.
53125296759031 is a deficient number, since it is larger than the sum of its proper divisors (7589328108441).
53125296759031 is an equidigital number, since it uses as much as digits as its factorization.
53125296759031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7589328108440.
The product of its (nonzero) digits is 15309000, while the sum is 58.
The spelling of 53125296759031 in words is "fifty-three trillion, one hundred twenty-five billion, two hundred ninety-six million, seven hundred fifty-nine thousand, thirty-one".
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