Base | Representation |
---|---|
bin | 11000001010001001100100… |
… | …11100010010000100000111 |
3 | 20222002201200021101101112102 |
4 | 30011010302130102010013 |
5 | 23430401101432242142 |
6 | 304553231401142315 |
7 | 14122114243515632 |
oct | 1405046234220407 |
9 | 228081607341472 |
10 | 53125296759047 |
11 | 15a223480573a7 |
12 | 5b6005648a99b |
13 | 2384903900696 |
14 | d193c70b6c19 |
15 | 621d9e37e532 |
hex | 305132712107 |
53125296759047 has 2 divisors, whose sum is σ = 53125296759048. Its totient is φ = 53125296759046.
The previous prime is 53125296758983. The next prime is 53125296759061. The reversal of 53125296759047 is 74095769252135.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53125296759047 - 26 = 53125296758983 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53125296759547) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26562648379523 + 26562648379524.
It is an arithmetic number, because the mean of its divisors is an integer number (26562648379524).
Almost surely, 253125296759047 is an apocalyptic number.
53125296759047 is a deficient number, since it is larger than the sum of its proper divisors (1).
53125296759047 is an equidigital number, since it uses as much as digits as its factorization.
53125296759047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 142884000, while the sum is 65.
The spelling of 53125296759047 in words is "fifty-three trillion, one hundred twenty-five billion, two hundred ninety-six million, seven hundred fifty-nine thousand, forty-seven".
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