Base | Representation |
---|---|
bin | 1100101010101… |
… | …0000100011011 |
3 | 10200222001100112 |
4 | 3022222010123 |
5 | 102100003103 |
6 | 5134354535 |
7 | 1213362362 |
oct | 312520433 |
9 | 120861315 |
10 | 53125403 |
11 | 27a959a1 |
12 | 1595ba4b |
13 | b010b66 |
14 | 70ac7d9 |
15 | 49e5cd8 |
hex | 32aa11b |
53125403 has 2 divisors, whose sum is σ = 53125404. Its totient is φ = 53125402.
The previous prime is 53125399. The next prime is 53125409. The reversal of 53125403 is 30452135.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 53125403 - 22 = 53125399 is a prime.
It is not a weakly prime, because it can be changed into another prime (53125409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26562701 + 26562702.
It is an arithmetic number, because the mean of its divisors is an integer number (26562702).
Almost surely, 253125403 is an apocalyptic number.
53125403 is a deficient number, since it is larger than the sum of its proper divisors (1).
53125403 is an equidigital number, since it uses as much as digits as its factorization.
53125403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1800, while the sum is 23.
The square root of 53125403 is about 7288.7175140761. The cubic root of 53125403 is about 375.9245996197.
Adding to 53125403 its reverse (30452135), we get a palindrome (83577538).
The spelling of 53125403 in words is "fifty-three million, one hundred twenty-five thousand, four hundred three".
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