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5312747873837 = 5333996202489
BaseRepresentation
bin100110101001111100001…
…1100110010011000101101
3200210220010112102020112202
41031103320130302120231
51144021001423430322
615144350452511245
71055555562553445
oct115237034623055
920726115366482
105312747873837
11176913a743088
1271979061b525
132c6cb3c89491
141451d1983125
15932e412d292
hex4d4f873262d

5312747873837 has 4 divisors (see below), whose sum is σ = 5313744081660. Its totient is φ = 5311751666016.

The previous prime is 5312747873827. The next prime is 5312747873897. The reversal of 5312747873837 is 7383787472135.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 5260022988676 + 52724885161 = 2293474^2 + 229619^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5312747873837 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5312747873827) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 498095912 + ... + 498106577.

It is an arithmetic number, because the mean of its divisors is an integer number (1328436020415).

Almost surely, 25312747873837 is an apocalyptic number.

It is an amenable number.

5312747873837 is a deficient number, since it is larger than the sum of its proper divisors (996207823).

5312747873837 is an equidigital number, since it uses as much as digits as its factorization.

5312747873837 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 996207822.

The product of its digits is 165957120, while the sum is 65.

The spelling of 5312747873837 in words is "five trillion, three hundred twelve billion, seven hundred forty-seven million, eight hundred seventy-three thousand, eight hundred thirty-seven".

Divisors: 1 5333 996202489 5312747873837