Base | Representation |
---|---|
bin | 111100011001101111110000… |
… | …0110000111111010000101101 |
3 | 2120200012011202221222112212201 |
4 | 1320303133200300333100231 |
5 | 1024114341304222334001 |
6 | 5121553423323501501 |
7 | 216624312101564320 |
oct | 17063374060772055 |
9 | 2520164687875781 |
10 | 531304110355501 |
11 | 144320898253a2a |
12 | 4b70a367687891 |
13 | 19a5c9bb649b92 |
14 | 952b382c307b7 |
15 | 416568c3c0501 |
hex | 1e337e0c3f42d |
531304110355501 has 32 divisors (see below), whose sum is σ = 633943835712000. Its totient is φ = 435639708870912.
The previous prime is 531304110355481. The next prime is 531304110355549. The reversal of 531304110355501 is 105553011403135.
It is not a de Polignac number, because 531304110355501 - 211 = 531304110353453 is a prime.
It is a super-2 number, since 2×5313041103555012 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (531304110355561) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 370110015 + ... + 371542771.
It is an arithmetic number, because the mean of its divisors is an integer number (19810744866000).
Almost surely, 2531304110355501 is an apocalyptic number.
It is an amenable number.
531304110355501 is a deficient number, since it is larger than the sum of its proper divisors (102639725356499).
531304110355501 is a wasteful number, since it uses less digits than its factorization.
531304110355501 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1449661.
The product of its (nonzero) digits is 67500, while the sum is 37.
Adding to 531304110355501 its reverse (105553011403135), we get a palindrome (636857121758636).
The spelling of 531304110355501 in words is "five hundred thirty-one trillion, three hundred four billion, one hundred ten million, three hundred fifty-five thousand, five hundred one".
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