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53131112440535 = 510626222488107
BaseRepresentation
bin11000001010010100011010…
…00101010110001011010111
320222010021200120121121202002
430011022031011112023113
523431000004241044120
6305000032431305515
714122411332141353
oct1405121505261327
9228107616547662
1053131112440535
1115a24861935a38
125b611ba07b29b
13238531c742a2c
14d197b9626463
156220dec09375
hex30528d1562d7

53131112440535 has 4 divisors (see below), whose sum is σ = 63757334928648. Its totient is φ = 42504889952424.

The previous prime is 53131112440531. The next prime is 53131112440547. The reversal of 53131112440535 is 53504421113135.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 53131112440535 - 22 = 53131112440531 is a prime.

It is a super-2 number, since 2×531311124405352 (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53131112440531) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5313111244049 + ... + 5313111244058.

It is an arithmetic number, because the mean of its divisors is an integer number (15939333732162).

Almost surely, 253131112440535 is an apocalyptic number.

53131112440535 is a deficient number, since it is larger than the sum of its proper divisors (10626222488113).

53131112440535 is a wasteful number, since it uses less digits than its factorization.

53131112440535 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10626222488112.

The product of its (nonzero) digits is 108000, while the sum is 38.

The spelling of 53131112440535 in words is "fifty-three trillion, one hundred thirty-one billion, one hundred twelve million, four hundred forty thousand, five hundred thirty-five".

Divisors: 1 5 10626222488107 53131112440535