Base | Representation |
---|---|
bin | 1111011101101001101… |
… | …00000111111000010111 |
3 | 1212210102020001011120100 |
4 | 13232310310013320113 |
5 | 32201113010240210 |
6 | 1044025454305143 |
7 | 53246320034445 |
oct | 7566464077027 |
9 | 1783366034510 |
10 | 531314540055 |
11 | 19536922a972 |
12 | 86b801b81b3 |
13 | 3b14496c010 |
14 | 1ba04095b95 |
15 | dc49d705c0 |
hex | 7bb4d07e17 |
531314540055 has 24 divisors (see below), whose sum is σ = 991787142528. Its totient is φ = 261570234816.
The previous prime is 531314540039. The next prime is 531314540087. The reversal of 531314540055 is 550045413135.
531314540055 is a `hidden beast` number, since 5 + 31 + 31 + 4 + 540 + 0 + 55 = 666.
It is not a de Polignac number, because 531314540055 - 24 = 531314540039 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 454114407 + ... + 454115576.
It is an arithmetic number, because the mean of its divisors is an integer number (41324464272).
Almost surely, 2531314540055 is an apocalyptic number.
531314540055 is a deficient number, since it is larger than the sum of its proper divisors (460472602473).
531314540055 is a wasteful number, since it uses less digits than its factorization.
531314540055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 908230007 (or 908230004 counting only the distinct ones).
The product of its (nonzero) digits is 90000, while the sum is 36.
The spelling of 531314540055 in words is "five hundred thirty-one billion, three hundred fourteen million, five hundred forty thousand, fifty-five".
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