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5313145441 is a prime number
BaseRepresentation
bin1001111001011000…
…00010101001100001
3111201021121202100111
410330230002221201
541340131123231
62235115051321
7245443663642
oct47454025141
914637552314
105313145441
11228714a89a
121043440b41
136689acb56
143858d76c9
152116b04b1
hex13cb02a61

5313145441 has 2 divisors, whose sum is σ = 5313145442. Its totient is φ = 5313145440.

The previous prime is 5313145381. The next prime is 5313145451. The reversal of 5313145441 is 1445413135.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5100102225 + 213043216 = 71415^2 + 14596^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5313145441 is a prime.

It is not a weakly prime, because it can be changed into another prime (5313145451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2656572720 + 2656572721.

It is an arithmetic number, because the mean of its divisors is an integer number (2656572721).

Almost surely, 25313145441 is an apocalyptic number.

It is an amenable number.

5313145441 is a deficient number, since it is larger than the sum of its proper divisors (1).

5313145441 is an equidigital number, since it uses as much as digits as its factorization.

5313145441 is an evil number, because the sum of its binary digits is even.

The product of its digits is 14400, while the sum is 31.

The square root of 5313145441 is about 72891.3262398209. The cubic root of 5313145441 is about 1744.9536735894.

Adding to 5313145441 its reverse (1445413135), we get a palindrome (6758558576).

The spelling of 5313145441 in words is "five billion, three hundred thirteen million, one hundred forty-five thousand, four hundred forty-one".