Base | Representation |
---|---|
bin | 1001111001011000… |
… | …00100000111001001 |
3 | 111201021122001120102 |
4 | 10330230010013021 |
5 | 41340131321213 |
6 | 2235115135145 |
7 | 245444020262 |
oct | 47454040711 |
9 | 14637561512 |
10 | 5313151433 |
11 | 2287154347 |
12 | 10434444b5 |
13 | 6689b27b5 |
14 | 3858d9969 |
15 | 2116b2158 |
hex | 13cb041c9 |
5313151433 has 2 divisors, whose sum is σ = 5313151434. Its totient is φ = 5313151432.
The previous prime is 5313151387. The next prime is 5313151439. The reversal of 5313151433 is 3341513135.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3761736889 + 1551414544 = 61333^2 + 39388^2 .
It is a cyclic number.
It is not a de Polignac number, because 5313151433 - 212 = 5313147337 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5313151396 and 5313151405.
It is not a weakly prime, because it can be changed into another prime (5313151439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2656575716 + 2656575717.
It is an arithmetic number, because the mean of its divisors is an integer number (2656575717).
Almost surely, 25313151433 is an apocalyptic number.
It is an amenable number.
5313151433 is a deficient number, since it is larger than the sum of its proper divisors (1).
5313151433 is an equidigital number, since it uses as much as digits as its factorization.
5313151433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 8100, while the sum is 29.
The square root of 5313151433 is about 72891.3673420934. The cubic root of 5313151433 is about 1744.9543295573.
Adding to 5313151433 its reverse (3341513135), we get a palindrome (8654664568).
The spelling of 5313151433 in words is "five billion, three hundred thirteen million, one hundred fifty-one thousand, four hundred thirty-three".
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