Base | Representation |
---|---|
bin | 100110101010001000010… |
… | …1010100000001001010011 |
3 | 200210221011211211210200222 |
4 | 1031110100222200021103 |
5 | 1144022314423403243 |
6 | 15144455044103255 |
7 | 1055601624611405 |
oct | 115242052401123 |
9 | 20727154753628 |
10 | 5313154122323 |
11 | 1769328a96633 |
12 | 719884694b2b |
13 | 2c704a1a7bb8 |
14 | 14522d8d2b75 |
15 | 93319b28168 |
hex | 4d510aa0253 |
5313154122323 has 2 divisors, whose sum is σ = 5313154122324. Its totient is φ = 5313154122322.
The previous prime is 5313154122233. The next prime is 5313154122343. The reversal of 5313154122323 is 3232214513135.
Together with previous prime (5313154122233) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5313154122323 - 232 = 5308859155027 is a prime.
It is not a weakly prime, because it can be changed into another prime (5313154122343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2656577061161 + 2656577061162.
It is an arithmetic number, because the mean of its divisors is an integer number (2656577061162).
Almost surely, 25313154122323 is an apocalyptic number.
5313154122323 is a deficient number, since it is larger than the sum of its proper divisors (1).
5313154122323 is an equidigital number, since it uses as much as digits as its factorization.
5313154122323 is an evil number, because the sum of its binary digits is even.
The product of its digits is 64800, while the sum is 35.
Adding to 5313154122323 its reverse (3232214513135), we get a palindrome (8545368635458).
The spelling of 5313154122323 in words is "five trillion, three hundred thirteen billion, one hundred fifty-four million, one hundred twenty-two thousand, three hundred twenty-three".
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