Base | Representation |
---|---|
bin | 1111011101101010111… |
… | …00110111110110110001 |
3 | 1212210102222010212212211 |
4 | 13232311130313312301 |
5 | 32201123224103241 |
6 | 1044030515252121 |
7 | 53246506605205 |
oct | 7566534676661 |
9 | 1783388125784 |
10 | 531325222321 |
11 | 195374266693 |
12 | 86b838aa041 |
13 | 3b146c3c29a |
14 | 1ba05676b05 |
15 | dc4ac80781 |
hex | 7bb5737db1 |
531325222321 has 2 divisors, whose sum is σ = 531325222322. Its totient is φ = 531325222320.
The previous prime is 531325222279. The next prime is 531325222327. The reversal of 531325222321 is 123222523135.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 443256350625 + 88068871696 = 665775^2 + 296764^2 .
It is a cyclic number.
It is not a de Polignac number, because 531325222321 - 211 = 531325220273 is a prime.
It is not a weakly prime, because it can be changed into another prime (531325222327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265662611160 + 265662611161.
It is an arithmetic number, because the mean of its divisors is an integer number (265662611161).
Almost surely, 2531325222321 is an apocalyptic number.
It is an amenable number.
531325222321 is a deficient number, since it is larger than the sum of its proper divisors (1).
531325222321 is an equidigital number, since it uses as much as digits as its factorization.
531325222321 is an evil number, because the sum of its binary digits is even.
The product of its digits is 21600, while the sum is 31.
Adding to 531325222321 its reverse (123222523135), we get a palindrome (654547745456).
The spelling of 531325222321 in words is "five hundred thirty-one billion, three hundred twenty-five million, two hundred twenty-two thousand, three hundred twenty-one".
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